Watts per meter-kelvin to BTU per hour-foot-degree Fahrenheit
Snapshot
1 Watts per meter-kelvin equals 0.577789 BTU per hour-foot-degree Fahrenheit. Conversion Encyclopedia uses the same fixed conversion basis across the calculator, common values, and reverse page for this page.
- Reference basis: This conversion uses a fixed factor based on physics reference unit model.
- Example: For 0.01 Watts per meter-kelvin, the result equals 0.005778 BTU per hour-foot-degree Fahrenheit.
- Use the reverse page if you need the opposite direction with the same basis.
Use the interactive calculator below for custom values and the common-value table for quick checks.
Interactive conversion
Converter Calculator
0.577789 BTU per hour-foot-degree Fahrenheit (BTU/(h·ft·°F))
SwitchMachine access
Available to apps and AI agents
Watts per meter-kelvin to BTU per hour-foot-degree Fahrenheit can be requested through Conversion Encyclopedia's structured interfaces by software and compatible AI agents. The identifiers below select the same calculation as the calculator.
Machine-readable identifiers
- Conversion family
thermal-conductivity- Source unit
watts_per_meter_kelvin- Target unit
btu_per_hour_foot_degree_fahrenheit
The JSON API and OpenAPI specification use the identifiers to reach the conversion engine. WebMCP lets compatible AI agents request the same calculation.
Example API request and response
POST /api/v1/convertRequest
{
"family": "thermal-conductivity",
"value": 1,
"from": "watts_per_meter_kelvin",
"to": "btu_per_hour_foot_degree_fahrenheit"
}Essential response
{
"ok": true,
"conversion": {
"family": "thermal-conductivity",
"value": 1,
"from": "watts_per_meter_kelvin",
"to": "btu_per_hour_foot_degree_fahrenheit",
"result": {
"raw": 0.5777892051642799,
"display": "0.577789"
},
"canonicalPath": "/thermal-conductivity/watts-per-meter-kelvin-to-btu-per-hour-foot-degree-fahrenheit/"
}
}Explanation
Formula: BTU per hour-foot-degree Fahrenheit = Watts per meter-kelvin × 0.577789. Why: the BTU-based engineering unit uses a fixed watts-per-meter-kelvin equivalent, so the calculator normalizes through W/(m·K) before applying the target unit.
Watts per meter-kelvin (W/(m·K)): the SI thermal-conductivity unit used in materials science, heat transfer, and engineering specifications.
BTU per hour-foot-degree Fahrenheit (BTU/(h·ft·°F)): an imperial/US engineering thermal-conductivity unit common in HVAC and building-material references.
This route is useful when comparing SI thermal-conductivity values with US engineering and HVAC references for insulation, building materials, and heat-transfer components.
This conversion is purely multiplicative because both units reduce through watts per meter-kelvin using fixed thermal-conductivity definitions with no offset.
Common Conversion Values
| Watts per meter-kelvin (W/(m·K)) | BTU per hour-foot-degree Fahrenheit (BTU/(h·ft·°F)) |
|---|---|
| 0.01 | 0.005778 |
| 0.1 | 0.057779 |
| 0.5 | 0.288895 |
| 1 | 0.577789 |
| 5 | 2.888946 |
| 10 | 5.777892 |
| 50 | 28.88946 |
| 100 | 57.778921 |
Questions & answers
Frequently Asked Questions
What result does this Watts per meter-kelvin to BTU per hour-foot-degree Fahrenheit page give for an input of 1?
For an input of 1 Watts per meter-kelvin, this page gives 0.577789 BTU per hour-foot-degree Fahrenheit.
Does this Watts per meter-kelvin to BTU per hour-foot-degree Fahrenheit page use the fixed W/(m·K) equivalent for BTU-based conductivity?
Yes. BTU per hour-foot-degree Fahrenheit uses a fixed watts-per-meter-kelvin equivalent on this page, so SI and US engineering conductivity values stay consistent across the direct answer, calculator, and table.
When would I convert watts per meter-kelvin to btu per hour-foot-degree fahrenheit?
This route is useful when comparing SI thermal-conductivity values with US engineering and HVAC references for insulation, building materials, and heat-transfer components.
How do I reverse Watts per meter-kelvin to BTU per hour-foot-degree Fahrenheit?
Use the mirror BTU per hour-foot-degree Fahrenheit to Watts per meter-kelvin route; it applies the inverse relationship with the same thermal-conductivity assumptions.