BTU per hour-foot-degree Fahrenheit to Watts per meter-kelvin
Snapshot
1 BTU per hour-foot-degree Fahrenheit equals 1.730735 Watts per meter-kelvin. Conversion Encyclopedia uses the same fixed conversion basis across the calculator, common values, and reverse page for this page.
- Reference basis: This conversion uses a fixed factor based on physics reference unit model.
- Example: For 0.01 BTU per hour-foot-degree Fahrenheit, the result equals 0.017307 Watts per meter-kelvin.
- Use the reverse page if you need the opposite direction with the same basis.
Use the interactive calculator below for custom values and the common-value table for quick checks.
Interactive conversion
Converter Calculator
1.730735 Watts per meter-kelvin (W/(m·K))
SwitchMachine access
Available to apps and AI agents
BTU per hour-foot-degree Fahrenheit to Watts per meter-kelvin can be requested through Conversion Encyclopedia's structured interfaces by software and compatible AI agents. The identifiers below select the same calculation as the calculator.
Machine-readable identifiers
- Conversion family
thermal-conductivity- Source unit
btu_per_hour_foot_degree_fahrenheit- Target unit
watts_per_meter_kelvin
The JSON API and OpenAPI specification use the identifiers to reach the conversion engine. WebMCP lets compatible AI agents request the same calculation.
Example API request and response
POST /api/v1/convertRequest
{
"family": "thermal-conductivity",
"value": 1,
"from": "btu_per_hour_foot_degree_fahrenheit",
"to": "watts_per_meter_kelvin"
}Essential response
{
"ok": true,
"conversion": {
"family": "thermal-conductivity",
"value": 1,
"from": "btu_per_hour_foot_degree_fahrenheit",
"to": "watts_per_meter_kelvin",
"result": {
"raw": 1.730735,
"display": "1.730735"
},
"canonicalPath": "/thermal-conductivity/btu-per-hour-foot-degree-fahrenheit-to-watts-per-meter-kelvin/"
}
}Explanation
Formula: Watts per meter-kelvin = BTU per hour-foot-degree Fahrenheit × 1.730735. Why: the BTU-based engineering unit uses a fixed watts-per-meter-kelvin equivalent, so the calculator normalizes through W/(m·K) before applying the target unit.
BTU per hour-foot-degree Fahrenheit (BTU/(h·ft·°F)): an imperial/US engineering thermal-conductivity unit common in HVAC and building-material references.
Watts per meter-kelvin (W/(m·K)): the SI thermal-conductivity unit used in materials science, heat transfer, and engineering specifications.
This route is useful when comparing SI thermal-conductivity values with US engineering and HVAC references for insulation, building materials, and heat-transfer components.
This conversion is purely multiplicative because both units reduce through watts per meter-kelvin using fixed thermal-conductivity definitions with no offset.
Common Conversion Values
| BTU per hour-foot-degree Fahrenheit (BTU/(h·ft·°F)) | Watts per meter-kelvin (W/(m·K)) |
|---|---|
| 0.01 | 0.017307 |
| 0.1 | 0.173074 |
| 0.5 | 0.865368 |
| 1 | 1.730735 |
| 5 | 8.653675 |
| 10 | 17.30735 |
| 50 | 86.53675 |
| 100 | 173.0735 |
Questions & answers
Frequently Asked Questions
What result does this BTU per hour-foot-degree Fahrenheit to Watts per meter-kelvin page give for an input of 1?
For an input of 1 BTU per hour-foot-degree Fahrenheit, this page gives 1.730735 Watts per meter-kelvin.
Does this BTU per hour-foot-degree Fahrenheit to Watts per meter-kelvin page use the fixed W/(m·K) equivalent for BTU-based conductivity?
Yes. BTU per hour-foot-degree Fahrenheit uses a fixed watts-per-meter-kelvin equivalent on this page, so SI and US engineering conductivity values stay consistent across the direct answer, calculator, and table.
When would I convert btu per hour-foot-degree fahrenheit to watts per meter-kelvin?
This route is useful when comparing SI thermal-conductivity values with US engineering and HVAC references for insulation, building materials, and heat-transfer components.
How do I reverse BTU per hour-foot-degree Fahrenheit to Watts per meter-kelvin?
Use the mirror Watts per meter-kelvin to BTU per hour-foot-degree Fahrenheit route; it applies the inverse relationship with the same thermal-conductivity assumptions.