PressureAtm to Bar

Atmospheres to Bar

Methodology·How We Verify

Snapshot

1 Atmospheres equals 1.01325 Bar.

Reference basis: This conversion uses exact pascal-based pressure definitions.
Example: For 0.1 Atmospheres, the result equals 0.101325 Bar.

Interactive conversion

Converter Calculator

Decimals: 1.5 or 1,5. Fractions: 1/2. Scientific notation: 1e3. Write 1000 without grouping separators.

1.01325 Bar (bar)

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API and AI agent access

Atmospheres to Bar.

Machine-readable identifiers

Conversion family: pressure
Source unit: atm
Target unit: bar

Use these identifiers in the API request. Sources and model limits also apply to software clients.

Example API request and response

POST /api/v1/convert

Request

{
  "family": "pressure",
  "value": 1,
  "from": "atm",
  "to": "bar"
}

Essential response

{
  "ok": true,
  "conversion": {
    "family": "pressure",
    "value": 1,
    "from": "atm",
    "to": "bar",
    "result": {
      "raw": 1.01325,
      "display": "1.01325"
    },
    "canonicalPath": "/pressure/atm-to-bar/"
  }
}

API, OpenAPI and WebMCP documentation

Explanation

Convert atm to pascals and divide by 100,000 Pa per bar.

Method & Reference

Method basis: exact conversion formula shown in Snapshot.
Applied factor: 1 Atmospheres = 1.01325 Bar (using exact pascal-based pressure definitions).
Consistency rule: calculator output and table values use the same constants and rounding policy.

Common Conversion Values

Atmospheres (atm)	Bar (bar)
0.1	0.101325
1/2	0.506625
1	1.01325
5	5.06625
10	10.1325
14.7	14.894775
29.92	30.31644
100	101.325
101.325	102.667556
1000	1,013.25

Questions & answers

Frequently Asked Questions

What is 1 atmospheres in bar?

1 Atmospheres equals 1.01325 Bar on this page.

When would I convert atmospheres to bar?

This route is useful when comparing metric engineering pressure values such as bar, kilopascals, and atmospheres across specifications, process equipment, and technical references.

How do I reverse Atmospheres to Bar?

Use the mirror Bar to Atmospheres route; it applies the inverse relationship with the same pressure assumptions.